Log entry time 07:18:24 on June23,2001

Entry number 64237

keyword=x=0.6, asymmetry

kinematics, x=0.6, June 23

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(1) transverse:
beam L/2// Target// left total N// left arm Araw// right total N// right arm Araw
IN // 270 // 6178 // -0.00272706 // 5904 // 0.00560029
OUT //270 // 7649 // -0.0182585 // 7273 // -0.018001

combine beam L/2 = IN and OUT:

N_L=13827, Araw_L = - 0.011319 +/- 0.00850
N_R=13177, Araw_R = + 0.012444 +/- 0.00871

From delta asymmetry runs #1455, 1456, 20455, 20456; with beam L/2 = IN,
left arm has positive asymmetry Adelta_L>0, right arm has Adelta_R<0; From existing
data (e94010) delta transverse asymmetry is positive. So left arm has positive
sign @ beam L/2 = IN.
(Although there is discrepancy between this analysis and the one Alexandre did,
we are confident about the signs of transverse asymmetry for both arms.

Then A_perp(raw) = -0.011868 +/- 0.006085, total N = 27004;

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(2) longitudinal:
beam L/2// Target// left total N// left arm Araw// right total N// right arm Araw
OUT // 0 // 18058 // -0.0179492 // 17250 // -0.0083973
IN // 0 // 19701 // -0.00541846 // 18893 // -0.0119434
IN // 180 // 8667 // 0.00758482 // 8098 // -0.00725716
OUT // 180 // 4638 // -0.0164883 // 3855 // -0.0268973

Target polarization @ 180 is 35%, @ 0 degree is 37%. If raw asymmetries are corrected/
normalized to 37%, then combined together, we will have:

left: Araw_L = -0.001304 +/- 0.00435
right: Araw_R = 0.002667 +/- 0.00456

where the sign of configuration "beam L/2 = OUT, target @ 0 degree" is temporarily defined
as positive.

Combine left and right arm results together, we have:

A_parallel(raw) = 0.0053715 +/- 0.003147

From 3he elastic asymmetry studied by Alexandre, (entry # 63133), configuration of
"beam half waveplate OUT + field 0 degree" should have the positive sign.

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(3) Extract A1:
A1(3he) = alpha * A_parallel - beta * A_perp
At x=0.6, alpha = 2.5554, beta = 0.5628,
A_perp/parallel = A_raw / (P_b*P_*f)

Beam polarization 80%, target 41%, f = 0.95 are used for transverse running;
target 37% is used for field @ 0 degree;
target 35% at field 180 degrees is corrected by normalizing target polarization.

Finally we have:

A1(3he) = 0.068536
A1n = 3 * A1(3he) = 0.205608;

statistical error:
deltaA1(3he) = sqrt(alpha**2/N_parallel + beta**2/N_perp)/(P_b*P_t*f) = 0.02875
deltaA1n(stat.) = 3 * deltaA1(3he)(stat.) = 0.086246.

User name X. Zheng

Log entry time 07:18:24 on June23,2001

Entry number 64237